Algorithm/PROGRAMMERS[MySQL]

Lv2. 동명 동물 수 찾기

씨니 2022. 5. 6. 20:46
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▶ 문제

 

▶ 풀이방법

SELECT NAME, COUNT(NAME) as "COUNT"
FROM ANIMAL_INS
WHERE NAME is not NULL
GROUP BY NAME
HAVING COUNT(NAME) >= 2
ORDER BY NAME;

- 일반 테이블 조건 : WHERE

- 집계값 조건 : HAVING

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