Algorithm/PROGRAMMERS[MySQL]
Lv2. 동명 동물 수 찾기
씨니
2022. 5. 6. 20:46
728x90
▶ 문제
▶ 풀이방법
SELECT NAME, COUNT(NAME) as "COUNT"
FROM ANIMAL_INS
WHERE NAME is not NULL
GROUP BY NAME
HAVING COUNT(NAME) >= 2
ORDER BY NAME;
- 일반 테이블 조건 : WHERE
- 집계값 조건 : HAVING
728x90